深度优先搜索和广度优先搜索(非递归).
深度优先:
- 将openlist中的最后一项取出.
-
将其未标记的邻项标记为已访问.并放入openlist.
-
重复此步骤1.2.直到openlist为空.
例:
上图中图从P开始,openlist:
[p] [r,s,q] [r,s,t] [r,s,u] [r,s] [r] []
广度优先则是将openlist中的第一项取出.有:
[p] [r,s,q] [s,q,u] [q,u] [u,t] [t] []
Grabbing the last element means you are using a "stack". Grabbing the first means you are using a "queue". -MLL
深度优先使用的是栈.广度优先使用的是队列.
伸展树
在上一篇博文中提到的伸展树(splay tree).其实自己也没怎么明白.在网上找了半天也没有看懂.最终找到了这个.这是加州大学伯克利分校的CS 61B数据结构的一个公开课视频.讲的清楚极了.现部分整理如下.
一.伸展树是一种平衡二叉搜索树.它可以快速的获得最近操作的项目.对于伸展树.最基本的策略是旋转(Rotation).旋转分为左旋和右旋.如下:
二.伸展树的基本操作:
1.查找(K):和普通的二叉树没什么区别.然后让查找结束的节点X成为根(splay)(不管是否找到目标K.)
2.伸展(splay X):有三种情况.
-
Zig-zag:
X是一个右节点的左节点.或者X是一个左节点的右节点.
旋转X两次.
-
Zig-zig:
X是一个左节点的左节点.或者X是一个右节点的右节点.
旋转两次.但和Zig-zag的旋转顺序有差异.先旋转X的父节点.在旋转X.
-
Zig:
X是根的子节点.
那么就是一次旋转
Zig-zag和Zig-zig都是对两层深度的操作.直到X成为根的子节点.就进行Zig操作.
下面是一个查找的例子.
首先.象普通的二叉搜索树一样.找到7.可见.7是一个右节点的右节点.那么就进行Zig-zig步骤.此时7是一个右节点的左节点.就进行Zig-zag步骤.再进行一个Zig步骤.一个查找7的操作就完成了.
3.插入(K):首先象普通的二叉搜索树一样将K插入.再将K伸展至根.
4.删除(K):象普通的二叉搜索树一样将K删除.然后将K的父节点X伸展至根.如果K没有在树内的话.那么就如同查找操作.即将最后一个访问的节点伸展至根.
这里有一个在线的示例:http://www.ibr.cs.tu-bs.de/courses/ss98/audii/applets/BST/SplayTree-Example.html
另一小段功能不全的测试代码..只能打印树的深度...(摊手)(摇头)
def inorder(): d=dict() def inner_inorder(n,r): if n is None : return else: inner_inorder(n.left,r=r+1) if d.get(r) is None: d[r]=[n.key] else: d[r].append(n.key) inner_inorder(n.right,r=r+1) inner_inorder(t.root,0) return d def print_tree(): d=inorder() for i in d: print "%s"%d[i] t=SplayTree() for i in range(9): t.insert(i) print_tree(t)
利用coverage测试python代码覆盖率
主程序是一个伸展树(Splay Tree).如下(链接):
class Node: def __init__(self, key): self.key = key self.left = self.right = None def equals(self, node): return self.key == node.key class SplayTree: def __init__(self): self.root = None self.header = Node(None) #For splay() def insert(self, key): if (self.root == None): self.root = Node(key) return self.splay(key) if self.root.key == key: # If the key is already there in the tree, don't do anything. return n = Node(key) if key < self.root.key: n.left = self.root.left n.right = self.root self.root.left = None else: n.right = self.root.right n.left = self.root self.root.right = None self.root = n def remove(self, key): self.splay(key) if key != self.root.key: raise 'key not found in tree' # Now delete the root. if self.root.left== None: self.root = self.root.right else: x = self.root.right self.root = self.root.left self.splay(key) self.root.right = x def findMin(self): if self.root == None: return None x = self.root while x.left != None: x = x.left self.splay(x.key) return x.key def findMax(self): if self.root == None: return None x = self.root while (x.right != None): x = x.right self.splay(x.key) return x.key def find(self, key): if self.root == None: return None self.splay(key) if self.root.key != key: return None return self.root.key def isEmpty(self): return self.root == None def splay(self, key): l = r = self.header t = self.root self.header.left = self.header.right = None while True: if key < t.key: if t.left == None: break if key < t.left.key: y = t.left t.left = y.right y.right = t t = y if t.left == None: break r.left = t r = t t = t.left elif key > t.key: if t.right == None: break if key > t.right.key: y = t.right t.right = y.left y.left = t t = y if t.right == None: break l.right = t l = t t = t.right else: break l.right = t.left r.left = t.right t.left = self.header.right t.right = self.header.left self.root = t
测试如下(链接):
import unittest from splay import SplayTree class TestCase(unittest.TestCase): def setUp(self): self.keys = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] self.t = SplayTree() for key in self.keys: self.t.insert(key) def testInsert(self): for key in self.keys: self.assertEquals(key, self.t.find(key)) def testRemove(self): for key in self.keys: self.t.remove(key) self.assertEquals(self.t.find(key), None) def testLargeInserts(self): t = SplayTree() nums = 40000 gap = 307 i = gap while i != 0: t.insert(i) i = (i + gap) % nums def testIsEmpty(self): self.assertFalse(self.t.isEmpty()) t = SplayTree() self.assertTrue(t.isEmpty()) def testMinMax(self): self.assertEquals(self.t.findMin(), 0) self.assertEquals(self.t.findMax(), 9) if __name__ == "__main__": unittest.main()
运行:
(rrandom)-(~/python-codes/udacity/RegehrCS258)-(07:27 下午 六 10月 06) -> py splayTest.py ..... ---------------------------------------------------------------------- Ran 5 tests in 1.454s OK
但是否每一行代码都运行过了呢?代码覆盖律(code coverage)就是指测试中代码的运行的程度.如果代码覆盖律小于100%.那就意味着还有语句没有被执行.这时候就要coverage出场了.
(rrandom)-(~/python-codes/udacity/RegehrCS258)-(07:42 下午 六 10月 06) -> coverage erase;coverage run splayTest.py; ..... ---------------------------------------------------------------------- Ran 5 tests in 2.294s OK
erase是清空上次的数据.coverage 还可以生成html,方便查看
(rrandom)-(~/python-codes/udacity/RegehrCS258)-(07:50 下午 六 10月 06) -> coverage erase;coverage run splayTest.py;coverage html -i ..... ---------------------------------------------------------------------- Ran 5 tests in 2.298s OK
得到结果:
Coverage report: 93%
Module | statements | missing | excluded | coverage |
---|---|---|---|---|
Total | 130 | 9 | 0 | 93% |
splay | 98 | 9 | 0 | 91% |
splayTest | 32 | 0 | 0 | 100% |
查看详细.是那些语句没有被执行:
excluded表示你告诉coverage忽略的代码.
现在尝试修改测试代码.删除一个不在树里的节点:
def testRemove(self): for key in self.keys: self.t.remove(key) self.assertEquals(self.t.find(key), None) self.t.remove(-999)
再次运行coverage:
(rrandom)-(~/python-codes/udacity/RegehrCS258)-(07:50 下午 六 10月 06) -> coverage erase;coverage run splayTest.py;coverage html -i ....E ====================================================================== ERROR: testRemove (__main__.TestCase) ---------------------------------------------------------------------- Traceback (most recent call last): File "splayTest.py", line 22, in testRemove self.t.remove(-999) File "/home/rrandom/python-codes/udacity/RegehrCS258/splay.py", line 39, in remove self.splay(key) File "/home/rrandom/python-codes/udacity/RegehrCS258/splay.py", line 86, in splay if key < t.key: AttributeError: 'NoneType' object has no attribute 'key' ---------------------------------------------------------------------- Ran 5 tests in 2.382s FAILED (errors=1)
这是一个不在预期内的错误.但是这一行却没有被执行.
那么错误应该在self.splay(key)内.
Python decorators
In python,a decorators starts with @,such as:
@myDecorator def func1(): print "inside func1()"
It means:
func1=myDecorator(func1)
Here is a useful decorator.
from functools import update_wrapper def decorator(d): "Make function d a decorator: d wraps a function fn." def _d(fn): return update_wrapper(d(fn), fn) update_wrapper(_d, d) return _d @decorator def memo(f): """Decorator that caches the return value for each call to f(args). Then when called again with same args, we can just look it up.""" cache = {} def _f(*args): try: return cache[args] except KeyError: cache[args] = result = f(*args) return result except TypeError: # some element of args can't be a dict key return f(*args) _f.cache = cache return _f
Then,implement it on fib
@memo def fib(n): if n == 0 or n == 1: return 1 else: return fib(n-1) + fib(n-2) print fib(100)
参考: